turunan kedua dari f(x) = 3x² + 7x + 2005 adalah...
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Jwbn :
[tex]\sf f(x) = 3x² + 7x + 2005[/tex]
[tex]\sf f'(x) = 2(3)x^{2 - 1} + 1(7)x^{1 - 1} + 0(2005)x^{0 - 1}[/tex]
[tex]\sf f'(x) = 6x¹ + 7x⁰ + 0[/tex]
[tex]\sf f'(x) = 6x + 7(1) + 0[/tex]
[tex]\sf f'(x) = 6x + 7[/tex]
[tex]\sf f"(x) = 1(6)x^{1 - 1} + 0(7)x^{0 - 1}[/tex]
[tex]\sf f"(x) = 6x⁰ + 0[/tex]
[tex]\sf f"(x) = 6(1) + 0[/tex]
[tex]\sf f"(x) = 6[/tex]
[tex]\purple{\boxed{\blue{\boxed{\green{\star{\red{\ \: \: \mathcal{5Riiz} \: \: \: {\green{\star}}}}}}}}}[/tex]
Jawaban:
[tex]f(x) = 3x^2 + 7x + 2005 [/tex]
[tex]f'(x) = 3.2x^{2-1} + 7 + 0 [/tex]
[tex]f'(x) = 6x + 7[/tex]
[tex]f''(x) = 6 + 0 [/tex]
[tex]\longrightarrow \red{\sf{f''(x) = 6}}[/tex]
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